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Let `vec(A)=4hat(i)+5hat(j)-hat(k), vec(b)=hat(i)-4hat(j)+5hat(k)` and `vec(c) =3hat(i)+hat(j)-hat(k)`. Find a vector `vec(d)` which is perpendicular to both `vec(a)` and `vec(b)`, and is such that `vec(d). Vec(c)=21`.

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Correct Answer - `d=7(hat(i)-hat(j)-hat(k))`
Let `vec(d)=d_(1) hat(i)+d_(2) hat(j)+d_(3)hat(k)`. Then,
`vec(b).vec(a)=0, vec(d).vec(b)=0` and `vec(d).vec(c)=21`
`implies {(4d_(1)+5d_(2)-d_(3)=0),(d_(1)-4d_(2)+5d_(3)=0):}}` and `3d_(1)+d_(2)-d_(3)=21`
`implies d_(1)/((25-4))=d_(2)/((-1-20))=d_(3)/((-16-5))=k` (say) `3d_(1)+d_(2)-d_(3)=21`
`implies (d_(1)=21k, d_(2)=-21k, d_(3)=-21k)` and `3d_(1)+d_(2)-d_(3)=21`
`implies 63 k-21 k+21k=21 implies k=1/3 implies d_(1)=7, d_(2)=-7` and `d_(3)=-7`.

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