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Four grams of graphite is burnt in a bomb calorimeter of heat capacity `30 kJ K^(-1)` in excess of oxygen at 1 atmospheric pressure. The temperature rises from 300 to 304 K. What is the enthalpy of combustion of graphite (in kJ `mol^(-1)`)
A. 360
B. 1440
C. `- 360`
D. `- 1440`

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Correct Answer - C
`DeltaE=CxxDeltatxx(M)/(m)=30xx4xx(12)/(4)=360`
`DeltaE=-360 kJ mol^(-1)`

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