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The correct thermodynamic conditions for the spontaneous reaction at all temperature is
A. `DeltaHlt0 and DeltaS=0`
B. `DeltaHgt0 and DeltaSlt0`
C. `DeltaHlt0 and DeltaSgt0`
D. `DeltaHlt0 and DeltaSlt0`

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Correct Answer - C
`DeltaG=DeltaH-T.DeltaS`
For, `DeltaHlt0` and `DeltaSgt0, DeltaG=-ve` (always)
`therefore` spontaneous at all temperatures.

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