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The enthalpy of vaporization of a liquid is `30 kJ mol^(-1)` and entropy of vaporization is 75 J `mol^(-1)` K. The boiling point of the liquid at 1 atm is
A. 250 K
B. 400 K
C. 450 K
D. 600 K

1 Answer

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Best answer
Correct Answer - B
`dS=(dQ_(rev))/(T), T= (30xx10^(3))/(75), T=400 K`.

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