Question

`60g` of compound on analysis gave `C = 24g, H= 4 g` and `O = 32g`. If Empirical formula is
A. `C_(2)H_(4)O_(2)`
B. `C_(2)H_(2)O`
C. `CH_(2)O_(2)`
D. `CH_(2)O`

Answer 1

Correct Answer - D
`{:("Element"," NO. of moles"," Simple ratio"),(C =24,24//12=2,1),(H=4,4//1=4,2),(O=32,32//16,1):}`
Therefore `CH_(2)O`.