Question

The number of unpaired electrons calculated in `[Co(NH_(3))_(6)]^(3+)` and `|CoF_(6)|^(3-)` are
A. 4 and 4
B. 0 and 2
C. 2 and 4
D. 0 and 4

Answer 1

Correct Answer - D
The formationof complex compound depends upon the nature of the ligand whether they are strong or weak.
The number of unpaired electrons `- [Co(NH_(3))_(6)]^(3+) rarr ` Inner orbital complex `, d^(2) sp^(3)` hybridisation
`Co^(3) rarr 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(0) 3d^(6)`

unpaired electron = zero (diamagnetic )
`[CoF_(6)]^(3-) rarr` Outer orbital complex, `sp^(3) d^(2)` hybridisation

Unpaired electrons `= `four (paramagnetic)