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In the complex ion `[Cu(CN_(4))]^(3-)` the hybridization state, oxidation state and number of unpaired electrons of copper are respectively
A. `dsp^(2, +1,1`
B. `sp^(3), +1`, zero
C. `sp^(3), +2,1`
D. `dsp^(3),+2,` zero

1 Answer

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Best answer
Correct Answer - B
`[Cu^(+1)(CN)_(4)^(-4)]^(-3)`
image
group state
CN is strong field ligand , `Delta ` is high
Excited State `:`
image
Hybridisation `=sp^(3)` , oxidation state of `Cu= +1`
Number of unpaired electron `=0`

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