Correct Answer - B
Moles of `CoCl_(3).6NH_(3) = ( 2.675)/(267.5) = (1)/(100) `mole `= 0.01` mole
Mole of `AgCl= (4.78 )/(143.5) = (3)/(100)` mole `=0.03` mole
0.01 mole of compound gives moles of `AgCl= 0.03` mole
So, 1 mole of compound gives moles of `AgCl = (0.03)/(0.01) = 3` mole. So, structural formula of compound having `3Cl^(-)` ions out side of coordination sphere, so formula is `[Co(NH_(3))_(6)]Cl_(3)`