Question

`AgCl` dissolves in ammonia solution giving
A. `Ag^(+), NH_(4)^(+) and Cl^(-)`
B. `Ag(NH_(3))^(+) and Cl^(-)`
C. `Ag_(2)(NH_(3))^(+) and Cl^(-)`
D. `Ag(NH_(3))_(2)^(+) and Cl^(-)`

Answer 1

Correct Answer - D
`AgCl+2NH_(3) to underset("complex")([Ag(NH_(3))_(2)]Cl)" "[Ag(NH_(3))_(2)]^(+)+Cl^(-)`