Question

GM of the numbers `3,3^2,3^3,...,3^n` is
A. `3^(2//n)`
B. `3^((n-1)/(2))`
C. `3^(n//2)`
D. `3^((n+1)/(2))`

Answer 1

Correct Answer - D
Clearly,
Required GM`=(3xx3^(2)xx3^(3) xx … xx3^(n))^(1//n)`
`rArr "Required "GM={3^(1+2+ ...+n)}^(1//n)=[3^((n(n+1))/(2))}^(1//n)=3^((n+1)/(2))`