Question

`lim_(xto0) (sin(picos^2x))/(x^2)` equals
A. `-pi`
B. ` pi`
C. `pi//2`
D. `1`

Answer 1

Correct Answer - B
`lim_(xto0)((sinpicos^2x))/(x^(2))((0)/(0)"from")`
` rArr lim_(ato0) (sin(pi-pisin^2x))/(x^2)`
` rArr lim_(ato0) (sin(pisin^2x))/(pisin^2x) pi ((sinx)/(x))^2=1xxpi(1)^2=pi`