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`lim_(xrarr oo)(1+sin.(1)/(n))^n` equals

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`lim_(xrarr oo)(1+sin.(1)/(n))^n` equals
A. `e^a`
B. `e`
C. `e^2a`
D. `0`
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Correct Answer - A
We have,
`lim_(xto oo) (1+sin(a)/(n))^n`
`=e^(lim_(ntooo) nsin.(a)/(n))=e^(lim_(ntooo)sin((a//a)/(a//n))xx a )=e^(1xxa)=e^(a)`
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