Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
202 views
in Chemistry by (94.4k points)
closed by
A gas formed by the action of alcoholic KOH on ethyl iodide, decolourises alkaline `KMnO_4` solution. The gas is
A. `CH_4`
B. `C_2H_6`
C. `C_2H_4`
D. `C_2H_2`

1 Answer

0 votes
by (93.2k points)
selected by
 
Best answer
Correct Answer - C
`CH_3CH_2I+KOH(Alc) to CH_2 =CH_2 +KI + H_2O`
`CH_2=CH_2+underset"Alk Pink"(KMnO_4)overset(H_2O)to underset("Colourless")(underset(OH)underset(|)CH_2-underset(OH)underset(|)CH_2+MnO_4)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...