Correct Answer - D
We know that the line of intersection of the planes `vecr.vecn_(1)=d_(1)` and `vecr.n_(2)=d_(2)` is parallel to `vecn_(1)xxvecn_(2)`.
Hence `vecn_(1)-3hati-hatj+hatk` and `vecn_(2)+4hatj-2hatk`
`:.` Required vector `=vecn_(1)xxvecn_(2)=|(hati,hatj,hatk),(3,-1,1),(1,4,-2)|=-2hati+7hatj+13hatk`