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The equation of the plane contaiing the lines `vecr=veca_(1)+lamda vecb` and `vecr=veca_(2)+muvecb` is

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The equation of the plane contaiing the lines `vecr=veca_(1)+lamda vecb` and `vecr=veca_(2)+muvecb` is
A. `[(vecr, veca, vecb)]=0`
B. `[(vecr,veca,vecb)]=veca.vecb`
C. `[(veca,vecb,veca)]=veca.vecb`
D. none of these
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Correct Answer - A
The required plane passes through the points having position vectors `veca` and `vecb`. It is perpendicular to `vecaxxvecb`.
So theequation of the plane is
`(vecr-veca).(vecaxxvecb)=0impliesvecr.(vecaxxvecb)=veca.(vecaxxvecb)implies[(vecr,veca,vecb)]=0`
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