Answer is : (c) SeF4 and CH4 have same shape
PH5 does not exist due to very less electronegativity difference between P and H. Hydrogen is slightly more electronegative than phosphorus, thus could not hold significantly the sharing electrons. On the other hand, BiCl5 does not exist due to inert pair effect. This is because on moving down the group, +5 oxidation state becomes less stable while +3 oxidation state become more stable due to inert pair effect.
In SO2, pπ-dπ and pπ-pπ both types of bonds are present.
SeF4 has sp3 d-hybridisation whereas CH4 has sp3 -hybridisation. Thus, they both have different geometry.
\(I^+_3\) has a bent shape due to the presence of 2 lone pairs on central I atom.