Correct Answer - D
If `vecp,vecq,vecr` are linearly independent vectors, then there exist scalars `x,y,z` not all zero such that
`xvecp+yvecq+zvecr=vec0`
`impliesvecp=(-y/x)vecq+((-z)/x)vecr`
`impliesvecp,vecq,vecr` are coplanar.
So, statement 2 is true.
We know that `[(vecpxxvecb,vecbxxvecc,veccxxveca)]=[(veca,vecb,vecc)]!=0` unless `veca,vecb,vecc` are coplanar.
So, statement -2 is not true.