Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.8k views
in Vectors by (93.2k points)
closed by
Find a vector of magnitude 15, which is perpendicular to both the vectors `(4hat(i) -hat(j)+8hat(k)) and (-hat(j)+hat(k)).`

1 Answer

0 votes
by (94.4k points)
selected by
 
Best answer
Let `vec(a) = (4 hat(i)-hat(j) + 8 hat(k) ) and vec(b)= (-hat(j) + hat(k)).`
A unit vector perpendicular to both `vec(a) and vec(b) = ((vec(a) xxvec(b)))/(|vec(a) xx vec(b)|`.
Now, `vec(a) xx vec(b) = |{:(hat(i),hat(j),hat(k)),(4,-1,8),(0,-1,1):}|`
`=(-1+8) hat(i) - ( 4-0) hat(j) + (-4-0) hat(k)`
`=(7 hat(i) - 4 hat(j) - 4 hat(k)).`
`:. |vec(a) xxvec(b)| = sqrt(7^(2) + (-4)^(2)+(-4)^(2)) =sqrt(81)=9.`
So, a unit vector perpendicular to both `vec(a) and vec(b)`.
`((vec(a) xxvec(b)))/|(vec(a) xx vec(b))| = (7 hat(i) -4 hat(j)- 4 hat(k))/9.`
The required vector `=(15(7hat(i)-4hat(j)-4hat(k)))/9 =5/3(7 hat(i) - 4 hat(j) - 4 hat(k)).`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...