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The compound that will react most readily with `NaOH` to from methanol is

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The compound that will react most readily with `NaOH` to from methanol is
A. `(CH_(3))_(4) overset(o+)(N)I^(theta)`
B. `CH_(3)OCH_(3)`
C. `(CH_(3))_(3) S^(o+) I^(theta)`
D. `(CH_(3))_(3)Cl`
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Correct Answer - `a`
`EN` of `N gt S`.
Positive charge on `N` will make `(Me)` group more `overline(e)` deficient than positive charge on `S`. Therefore (a) will undergo `SN^(2)` reaction more rapidly than (c).
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