Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
98 views
in Number System by (93.2k points)
closed by
Let `Z` be the set of all integers and `R` be the relation on `Z` defined as `R={(a , b); a , b in Z ,` and `(a-b)` is divisible by `5.}` . Prove that `R` is an equivalence relation.
A. reflexive
B. reflexive but not symmetric
C. symmetric and transitive
D. an equivalence relation

1 Answer

0 votes
by (94.4k points)
selected by
 
Best answer
Correct Answer - D
For reflexive :
(a, a)=a-a=0 is divisible by 5.
For symmetric :
If (a-b) is divisible by 5, then b-a=-(a-b) is also divisible by 5.
Thus relation is symmetric.
For transitive
If (a-b) and (b-c) is divisible by 5.
Then (a-c) is also divisible by 5
Thus relation is transitive
`therefore R` is an equivalence relation.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...