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If `log_a(ab)=x` then `log_b(ab)` is equals to
A. `(1)/(x)`
B. `(x)/(x+1)`
C. `(x)/(1-x)`
D. `(x)/(x-1)`

1 Answer

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Best answer
Correct Answer - D
`log_(a)ab=x`
`log_(a)a+log_(b)b=x`
`(1)/(log_(b)a)=x-1`
`log_(b)a=(1)/(x-1)" ....(1)"`
`log_(b)ab=log_(b)a+log_(b)b`
`=(1)/(x-1)+1" (From(1))"`
`=(1+x-1)/(x-1)`
`log_(b)ab=(x)/(x-1)`

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