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If the area of a triangle with vertices `(-3,0),(3,0)` and `(0,0` is 9 sq. units. Then the value of `k` will be

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If the area of a triangle with vertices `(-3,0),(3,0)` and `(0,0` is 9 sq. units. Then the value of `k` will be
A. 3
B. 6
C. 9
D. 12
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Correct Answer - A
Let the vertices of the `Delta ABC` be
`A(-3, 0), B(3, 0)` and `C (0, k)`.
`:.` Area of `Delta ABC=1/2 |(,,),(,,),(,,)|`
Given, area is 9
`implies 9=1/2 {-3(-k)+1(3k)}`
`implies 18=3k+3k`
`implies k=18/6=3`
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