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Find the greatest no. that will divide 93, 111 and 129, leaving remainder 3 in each case.

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Best answer

Since Remainder is 3 in each case numbers are

93 – 3 = 90

111 – 3 = 108

129 – 3 = 126

Required number will be HCF of 90,108 and 126 HCF of 90 and 108

So. Greatest number will be =18

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