Question

The centre of circle inscribed in a square formed by lines `x^2-8x+12=0a n dy^2-14 y+45=0` is `(4,7)` `(7,4)` `(9,4)` `(4,9)`
A. (4, 7)
B. (7, 4)
C. (9, 4)
D. (4, 9)

Answer 1

Correct Answer - A
The equation of the sides of the square are `x=2, x=6, y=5` and `y=9`. Therefore, the coordinates of the end points of a diameter are (2, 5) and (6, 9). So, the centre of the square has the coordinates `((2+6)/(2), (5+9)/(2))=(4, 7)`.
Hence, the coordinates of the centre of the circle are (4, 7).