(b) As `E_(1) = L_(1) (dI)/(dt)`
& `E_(1)I = L_(1) Id//dt`
`dw_(1) = E_(1)I dt = L_(1) IdI_(1)`, Integrating
`w_(1) = (1)/(2) L_(1)I^(2)`
Similarly, `w_(2) = (1)/(2) L_(2) I^(2)`
As the circuits are purely ideal i.e., ohmic resistances are zero.
`:.` Power consumed by the two circuits is zero.