`mu=(sin(A+delta_(m)))/(sin-A/2)`
`mu=16/((4sqrt2//5))=(1.6xx5)/(4sqrt2), A=60^(@)`
`(1.6xx5)/(4sqrt2)=(sin(60+delta_(m)/2))/(sin""60/2)`
`(1.6xx5)/(4sqrt2)xx1/2=sin((60+delta_m)/2)`
`sin((60+delta_(m))/2)=1/sqrt2`
`(60+delta_(m))/2=45^(@)`
`60+delta=90^(@)`
`delta_(m)=30^(@)`