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Limiting molar conductivity of `NH_(4)OH` (i.e., `overset(0)(wedge)_(m(NH_(4)OH))`) is equal to
A. `overset(0)(wedge)_(m(NH_(4)Cl))+overset(0)(wedge)_(m(NaCl))-overset(0)(wedge)_(m(NaOH))`
B. `overset(0)(wedge)_(m(NaOH))+overset(0)(wedge)_(m(NaCl))-overset(0)(wedge)_(m(NH_(4)Cl))`
C. `overet(0)(wedge)_(m(NH_(4)OH))+overset(0)(wedge)_(m(NH_(4)Cl))-overset(0)(wedge)_(m(HCl))`
D. `overset(0)(wedge)_(m(NH_(4)Cl))+overset(0)(wedge)_(m(NaOH))-overset(0)(wedge)_(m(NaCl))`

1 Answer

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Best answer
Correct Answer - D
`(wedge)_(m(NH_(4)OH))=overset(0)(wedge)_(m(NH_(4)Cl))+overset(0)(wedge)_(m(NaOH))-overset(0)(wedge)_(M(NaCl))`

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