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For the cell reaction
`Cu^(2+)(C_(1aq))+Zn_((s))+Zn^(2+)(C_(2aq))+Cu_((s))`
of an electrochemical cell, the change in free energy at a given temperature is a function of
A. ln `(C_(1))`
B. ln `(C_(2))`
C. ln `(C_(1)+C_(2))`
D. ln `(C_(2)//C_(1))`

1 Answer

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Best answer
Correct Answer - D
`E_(cell)=E_(cell)^(@)-(RT)/(nF)` In `(C_(2))/(C_(1)) and DeltaG=-nFE_(cell)`
Hence `DeltaG` is the function of `ln ((C_(2))/(C_(1)))`

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