Question

When `E_(Ag^+//Ag)^(o)=0.8` volt and `E_(Zn^(2+)//Zn)^(o)=-0.76` volt, which of the following is correct
A. `Ag^(+)` can be reduced by `H_(2)`
B. Ag can oxidise `H_(2)` into `H^(+)`
C. `Zn^(2+)` can be reduced by `H_(2)`
D. Ag and reduce `Zn^(2+)` ion

Answer 1

Correct Answer - A
Because `H_(2)` has greater reduction potential so it reduced at `Ag^(+)`.