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1.25g of a solid dibasic acid is completely neutralised by 25mL of 0.25 molar `Ba(OH_(2))` solution. Molecular mass of the acid is:
A. 100
B. 150
C. 120
D. 200

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Correct Answer - D
Molarity `=(W(gm)xx1000)/(V(ml)xx"molecular weight")`
`0.25=(1.25xx1000)/(25xx"molecular weight")`
`:.` Molecular weight `=(1.25xx1000)/(0.25xx25)=200`.

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