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The number of oxygen atoms in 4.4 g of `CO_(2)` is approx
A. `1.2xx10^(23)`
B. `6xx10^(22)`
C. `6xx10^(23)`
D. `12xx10^(23)`

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Correct Answer - A
44 g of `CO_(2)` has `2xx6xx10^(23)` atoms of oxygen
4.4 g of `CO_(2)` has `=(12xx10^(23))/44 xx4.4=1.2xx10^(23)` atoms.

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