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The maximum amount of `BaSO_(4)` precipitated on mixing equal volumes of `BaCl_(2)` (0.5 M) with `H_(2)SO_(4)` (1 M) will correspond to
A. 0.5 M
B. 1.0 M
C. 18 moles
D. 100 moles

1 Answer

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Best answer
Correct Answer - A
`BaCl_(2)+H_(2)SO_(4) rarr BaSO_(4)+2HCl`
One mole of `BaCl_(2)` reacts with one mole of `H_(2)SO_(4)`.
Hence 0.5 mole will react with 0.5 mole of `H_(2)SO_(4)` i.e. `BaCl_(2)` is the limiting reagent.

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