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The molarity of orthophosphoric acid having purity of 70% by weight and specific gravity 1.54 would be
A. 11 M
B. 22 M
C. 33 M
D. 44 M

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Correct Answer - A
70% by weight 70 gm `H_(3)PO_(4) rarr 100` gm solution/sample
`V=W/d=100/1.54" "M=(70xx1000)/(98xx100//1.54)=11M`

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