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The oxidation number of N in `NH_(4)Cl` is

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The oxidation number of N in `NH_(4)Cl` is
A. `+5`
B. `+3`
C. `-5`
D. `-3`
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Correct Answer - D
`NH_(4)Cl" "NH_(4)^(+)+Cl^(-)`
`overset(**)(N)H_(4)^(+)`
`x+4=+1, x=1-=-3`.
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