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[NiCl4]2− is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral.
Why?

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But CO is a strong field ligand. Therefore, it causes the pairing of unpaired 3d electrons. Also, it causes the 4s electrons to shift to the 3d orbital, thereby giving rise to sp3 hybridization. Since no unpaired electrons are present in this case, [Ni(CO)4] is diamagnetic.

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