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200 V , 0.2 ऐम्पियर धारा वाले बल्ब के तन्तु के तार की लम्बाई 20 सेमी है । तन्तु के प्रदार्थ का विशिष्ट प्रतिरोध `5xx10^(-7)` ओम - मीटर है । तार के व्यास की गणना कीजिए ।

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`R=(lp)/(pir^(2))=(4lp)/(piD^(2))`
`D^(2)=(4lp)/(piR)=(4xx20xx10^(-2)xx5xx10^(-7))/(3.14xx1000)`
`=1.274xx10^(-10)`
`D = 1.13xx10^(-5)` मी ।

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