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If `costheta_1 2costheta_2,` then `tan(theta_(1-theta_2))/2tan(theta_1+theta_2)/2` is equal to `1/3` (b) `-1/3` `1` (d) `-1`
A. `(1)/(3)`
B. `-(1)/(3)`
C. 1
D. `-1`

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Best answer
Correct Answer - B
`sin27^(@)-sin63^(@)=-2cos45^(@)sin18^(@)`
`rArr tan(x+y)=((4sqrt(5))/(3sqrt(3)))/(1-(15)/(27))=(4sqrt(5)xx27)/(12xx3sqrt(3))=sqrt(13)`

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