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The roots of the equation `4x^2-2sqrt5 x +1=0` are .
A. `sin36^(@),sin18^(@)`
B. `sin18^(@),cos36^(@)`
C. `sin36^(@),cos18^(@)`
D. `cos 18^(@),cos36^(@)`

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Correct Answer - B
`4x^(2)-2sqrt(5)x+1=0`
`therefore x=(2sqrt(5)+-2)/(8)=(sqrt(5)+-1)/(4)`
`therefore` Roots are `sin 18^(@)` and `cos36^(@)`

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