Correct Answer - D
We have `sin^(3)10^(@)+sin^(3)50^(@)-sin^(3)70^(@)`
`=(1)/(4)[(3sin10^(@)-sin30^(@))+(3sin50^(@)-sin150^(@))-(3sin70^(@)-sin210^(@))]`
`=(1)/(4)[3(sin10^(@)+sin50^(@)-sin70^(@))-(3)/(2)]`
`=(1)/(4)[3(sin 10^(@)-2cos60^(@).sin10^(@))-(3)/(2)]=-(3)/(8)`