Question

An object is thrwon vertically upwards with a velocity of 60 m/s. After what time it strike the ground ? Use `g=10m//s^(2)`.

Answer 1

Let the the time of ascent of the particle be t
using `v=u-"gt"`
`t=(-u)/(-g)=(60)/(10)=6s`
As the time of ascent is equal to the time of descent, therefore
`t=6+6=12s`.