Correct Answer - A
`because A.M. ge G.M. therefore (2^(sin x)+2^(cos x))/(2)ge sqrt(2^(sin x).2^(cos x))`
`therefore 2^(sin x)+2^(cos x)ge 2. sqrt(2^(sin x + cos x))`
But minimum value of cos x + sin x is `- sqrt(2)`
`thereofre 2^(sin x)+2^(cos x)ge 2. sqrt(2^(-sqrt(2)))=2^(1-(1)/(sqrt(2)))`
But the given equation is `2^(sin x)+2^(cos x)=2^(1-(1)/(sqrt(2)))`, which can hold only if `2^(sin x)=2^(cos x)=2^(-(1)/(sqrt(2)))`
`rArr x = 2n pi + (5pi)/(4), n in Z`