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If `tanbeta = costheta*tanalpha` , then `tan^2(theta/2)` is equal to

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If `tanbeta = costheta*tanalpha` , then `tan^2(theta/2)` is equal to
A. `(sin(alpha+beta))/(sin(alpha-beta))`
B. `(cos(alpha-beta))/(cos(alpha+beta))`
C. `(sin(alpha-beta))/(sin(alpha+beta))`
D. `(cos(alpha+beta))/(cos(alpha-beta))`
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Correct Answer - C
`"tan"^(2)(theta)/(2)=(1-cos theta)/(1+cos theta)=(tan alpha - tan beta)/(tan alpha + tan beta)=(sin(alpha-beta))/(sin(alpha+beta))`
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