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If ` log_(a)b=2, log_(b)c=2, and log_(3) c= 3 + log_(3)` a,then the value of c/(ab)is ________.
A. 1
B. 3
C. 9
D. 27

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Correct Answer - B
`log_(3)C=3+log_(3)a`
`rArr "log"_(3)(c )/(a)=3`
`rArr c = 27 a` ….(1)
`log_(a)b=2` and `log_(b)c=2`
`rArr log_(a)b.log_(b)c=4`
`rArr log_(a)c=4`
`rArr c = a^(4)` ….(2)
From (1) and (2), we get
a = 3 and c = 81
`therefore` from `log_(a)b = 2`, we get `b = a^(2) = 9`
`rArr (c )/(ab)=3`

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