Question

Find the pressure exerted at the tip of a board pin, of area 0.1 `mm^(2)`, if it is pressed against the board with a force 15 N.

Answer 1

Normal force applied on the pin, F = 15 N
Area of the tip of the board pin, A = 0.1 `mm^(2)`
= `0.1 xx 10^(-6) m^(2)`
Pressure, `P = (F)/(A) = (15)/(0.1 xx 10^(-6)) N m^(-2)`
`= 15 xx 10^(7) N m^(2)`