Question

The angle of minimum deviation produced by a `60^(@)` prism is `40^(@)`. Calculate the refractive index of the material of the prism.

Answer 1

`A = 60^(@), delta = 40^(@), mu = ?`
The refractive index of the material of the prism,
`mu = (sin[(A+delta)/(2)])/(sin.(A)/(2)) = (sin[(60^(@)+40^(@))/(2)])/(sin[(60^(@))/(2)] ) = (sin 50^(@))/(sin 30^(@)) = (0.7660)/((1)/(2)) = (0.7660)/(1) xx 2 = 1.532`