Question

If one root of the equation `z^2-a z+a-1=0i s(1+i),w h e r ea` is a complex number then find the root.

Answer 1

Correct Answer - z=1
`z^(2) -az + a 1 =0`
Putting z = 1 + i
a=2+i
`rArr z^(2) - (2+i)z + 1 + i=0` is the equaiton
`rArr z = 1` is the other roots