Question

Calculate the maximum energy that a `beta` particle can have in the following decay:
`._(8)O^(19) to ._(9)F^(19)+._(-1)e^(0)+barnu`
Given, `m(._(8)O^(19))=19.003576u, m(._(9)F^(19))=18.998403u, m(._(-1)e^(0))=0.000549u`

Answer 1

Correct Answer - 4.3049 MeV
Q-value of `beta`-decay =`(m(._8O^19) -{m(._9F^19) + m(._(-1)e^0)}`
The energy is shared by `beta^-` particle , if `barv` does not get any share.