Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
246 views
in Physics by (93.5k points)
closed by
When the voltage drop across a p-n junction is increased from 0.80 V to 0.82 V, the change in the diode current is 20 mA. What is the dynamic resistance of the diode ?

1 Answer

0 votes
by (92.5k points)
selected by
 
Best answer
`Delta V=0.82-0.800 =0.02 V`
`Deltal =20 mA =20xx10^(-3) A`
`:. ` Dynamic resistance `r_(d)=(DeltaV)/(Deltal)=0.02/(20xx10^(-3))`
`r_(d)=1 Omega`

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...