Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
132 views
in Trigonometry by (93.5k points)
closed by
Find the value of `cot^(-1)(-sqrt3)+cosec^(-1)(2)+sec^(-1)(-sqrt2)`.

1 Answer

0 votes
by (92.5k points)
selected by
 
Best answer
Since the principal values of `cot^(-1)x,cosec^(-1)x and sec^(-1)x"lie in "(0,pi), {-pi/2,pi/2]-{0} and [0.pi]-{pi/2}` respectively and in these intervals `cot ((5pi)/6)=-sqrt3,cosec.(pi/6)=2,sec((3pi)/4)=-sqrt2`
`:.cot^(-1)(-sqrt3)=(5pi)/6,cosec^(-1)(2)=pi/6,sec^(-1)(-sqrt2)=(3pi)/4`
`:. cot^(-1)(-sqrt3)+cosec^(-1)(2)=pi/6,sec^(-1)(-sqrt2)=(3pi)/4`
`:.cot^(-1)(-sqqrt3)+cosec^(-1)(2)+sec^(-1)(-sqrt2)`
`(5pi)/6+pi/6+(3pi)/4`
`=(7pi)/4`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...