Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
211 views
in Mathematics by (97.5k points)
closed by
The area bounded by `y=x^(2)+2 and y=2|x|-cospi x` is equal to
A. `2//3`
B. `8//3`
C. `4//3`
D. `1//3`

1 Answer

0 votes
by (94.7k points)
selected by
 
Best answer
Correct Answer - B
Solving given curves
`x^(2)+2=2|x|-cos pix`
`rArr" "x^(2)-2|x|+2=-cos pix`
`rArr" "(|x|-1)^(2)+1=-cospix`
`rArr" "x=pm1`
`therefore" Required Area "=int_(-1)^(1)(x^(2)+2-2|x|+cospix)dx=8//3`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...